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gitlab: use $MAKE instead of 'make'

The lcitool generated containers have '$MAKE' set to the path
of the right 'make' binary. Using the env variable makes it
possible to override the choice per job.

Signed-off-by: Daniel P. Berrangé <berrange@redhat.com>
Reviewed-by: Thomas Huth <thuth@redhat.com>
Reviewed-by: Philippe Mathieu-Daudé <philmd@linaro.org>
Message-ID: <20240513111551.488088-3-berrange@redhat.com>
Signed-off-by: Thomas Huth <thuth@redhat.com>
Daniel P. Berrangé 1 year ago
parent
commit
c53f7a1078
1 changed files with 3 additions and 3 deletions
  1. 3 3
      .gitlab-ci.d/buildtest-template.yml

+ 3 - 3
.gitlab-ci.d/buildtest-template.yml

@@ -26,10 +26,10 @@
       then
         pyvenv/bin/meson configure . -Dbackend_max_links="$LD_JOBS" ;
       fi || exit 1;
-    - make -j"$JOBS"
+    - $MAKE -j"$JOBS"
     - if test -n "$MAKE_CHECK_ARGS";
       then
-        make -j"$JOBS" $MAKE_CHECK_ARGS ;
+        $MAKE -j"$JOBS" $MAKE_CHECK_ARGS ;
       fi
     - ccache --show-stats
 
@@ -60,7 +60,7 @@
     - cd build
     - find . -type f -exec touch {} +
     # Avoid recompiling by hiding ninja with NINJA=":"
-    - make NINJA=":" $MAKE_CHECK_ARGS
+    - $MAKE NINJA=":" $MAKE_CHECK_ARGS
 
 .native_test_job_template:
   extends: .common_test_job_template